C Program to Check Armstrong Number
C Programming Language Loop control in C Language (Article) Loop control in C Language (Program)
500
Program:
#include int main() { int num, originalNum, remainder, result = 0; printf("Enter a three-digit integer: "); scanf("%d", &num); originalNum = num; while (originalNum != 0) { // remainder contains the last digit remainder = originalNum % 10; result += remainder * remainder * remainder; // removing last digit from the orignal number originalNum /= 10; } if (result == num) printf("%d is an Armstrong number.", num); else printf("%d is not an Armstrong number.", num); return 0; }
Output:
Enter a three-digit integer: 371 371 is an Armstrong number.
Explanation:
Check Armstrong Number of n digits
#include #include int main() { int num, originalNum, remainder, n = 0; float result = 0.0; printf("Enter an integer: "); scanf("%d", &num); originalNum = num; // store the number of digits of num in n for (originalNum = num; originalNum != 0; ++n) { originalNum /= 10; } for (originalNum = num; originalNum != 0; originalNum /= 10) { remainder = originalNum % 10; // store the sum of the power of individual digits in result result += pow(remainder, n); } // if num is equal to result, the number is an Armstrong number if ((int)result == num) printf("%d is an Armstrong number.", num); else printf("%d is not an Armstrong number.", num); return 0; }
Output
Enter an integer: 1634 1634 is an Armstrong number.
In this program, the number of digits of an integer is calculated first and stored in n
. And, the pow()
function is used to compute the power of individual digits in each iteration of the second for
loop.
This Particular section is dedicated to Programs only. If you want learn more about C Programming Language. Then you can visit below links to get more depth on this subject.