Armstrong Numbers Between Two Integers using c program

C Programming Language Loop control in C Language (Article) Loop control in C Language (Program)

118

---

Tip: Before trying this program, learn what is armstrong-number

Given Input:

Enter two numbers(intervals): 200
2000

Expected Output:

Armstrong numbers between 200 and 2000 are: 370 371 407 1634 

Program:

#include <math.h>
#include <stdio.h>
int main() {
  int low, high, number, originalNumber, rem, count = 0;
  double result = 0.0;
  printf("Enter two numbers(intervals): ");
  scanf("%d %d", &low, &high);
  printf("Armstrong numbers between %d and %d are: ", low, high);

  // swap numbers if high < low
  if (high < low) {
    high += low;
    low = high - low;
    high -= low;
  }
   
  // iterate number from (low + 1) to (high - 1)
  // In each iteration, check if number is Armstrong
  for (number = low + 1; number < high; ++number) {
    originalNumber = number;

    // number of digits calculation
    while (originalNumber != 0) {
      originalNumber /= 10;
      ++count;
    }

    originalNumber = number;

    // result contains sum of nth power of individual digits
    while (originalNumber != 0) {
      rem = originalNumber % 10;
      result += pow(rem, count);
      originalNumber /= 10;
    }

    // check if number is equal to the sum of nth power of individual digits
    if ((int)result == number) {
      printf("%d ", number);
    }

    // resetting the values
    count = 0;
    result = 0;
  }

  return 0;
}

Output:

Enter two numbers(intervals): 200
2000
Armstrong numbers between 200 and 2000 are: 370 371 407 1634 

Explanation:

---

---