- A2%
- B2.02%
- C4%
- D4.04%
Area - Quiz
- A7200 m2
- B15000 m2
- C13500 m2
- D54000 m2
- A12 cm
- B8 cm
- C6 cm
- D2 cm
- A900 sq. m.
- B800 sq. m.
- C750 sq. m.
- D950 sq. m.
- A96 m2
- B90 m2
- C99 m2
- D93 m2
- ARs. 87.50
- BRs. 84.70
- CRs. 87.20
- DRs. 77.50
- A21.92 m2
- B17.92 m2
- C22.92 m2
- D25.92 m2
- A34.56 %
- B32.43 %
- C29.45 %
- D45.24 %
Results:
🟢 Correct Answers: 🔴 Wrong Answers:
🟢 Correct Answers: 🔴 Wrong Answers:
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Quiz Information
Quiz Information
Quiz Platform FAQ
General Information
- Number of Questions: Each quiz consists of 10 questions.
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- Correct Option for each question.
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Quiz Analytics
Area - Quiz
Guest User
Time Taken: Questions: Answered: Not Answered:
Correct Answer:
Wrong Answer:
Percentage: %
- A. 2%
- B. 2.02%
- C. 4%
- D. 4.04%
Remarks:
Explanation:
The percentage error in the calculated area of the square is 4.04%.
This is calculated by taking the difference between the actual area and the measured area, and then expressing it as a percentage of the actual area.
In this case, the actual area is 100cm x 100cm = 10000 cm2 and the measured area is 102cm x 102cm = 10404 cm2
The difference (10404 - 10000) = 404 cm2 which is 4.04% of the actual area.
- A. 7200 m<sup>2 </sup>
- B. 15000 m<sup>2 </sup>
- C. 13500 m<sup>2 </sup>
- D. 54000 m<sup>2 </sup>
Remarks:
Explanation:
Let the length of the rectangle be 5x, and breadth be 3x,
Perimeter of a rectangle = 2(l +b) = 480
2(5x + 3x) = 480
2 x 8x = 480
16x = 480
x = 480/16 = 30
∴ Length = 5 x 30 = 150 m
Breadth = 3 x 30 = 90 m
And, Area of rectangle = L x B
= 150 x 90 = 13500 m2
- A. 12 cm
- B. 8 cm
- C. 6 cm
- D. 2 cm
Remarks:
Explanation:
Perimeter of Square = 4 x side 4 x side = 24 Side = 24/4 = 6 cm One of the sides of the square is 6 cm.
- A. 900 sq. m.
- B. 800 sq. m.
- C. 750 sq. m.
- D. 950 sq. m.
Remarks:
Explanation:
Area of a square = 1/2 (diagonal) 2 = 1/2 (40)2 = 1/2 * 1600 = 800 sq. m.
- A. 96 m<sup>2</sup>
- B. 90 m<sup>2</sup>
- C. 99 m<sup>2</sup>
- D. 93 m<sup>2</sup>
Remarks:
Explanation:
When d1 and d2 are the diagonals of rhombus then, The Side of rhombus = Area Aptitude Area Aptitude Squaring both sides 202 = 16^2 + d2^2 400 = 256 + d2^2 d2^2 = 400 - 256 d2 = √144 d2 = 12 Area of rhombus =1/2( d1 × d2 ) =1/2 ( 16 × 12 )=96 cm^2
- A. 5: 4
- B. 2.25 : 1
- C. 4: 5
- D. 4: 7
Remarks:
Explanation:
The ratio between the new area and the original area of the square can be found by using the formula for the area of a square and the percentage increase in the side length. The original area of the square is s^2, where s is the side length. After the side length is increased by 50%, the new side length is 1.5s. The new area of the square is (1.5s)^2 = 2.25s^2. To find the ratio between the new area and the original area, we divide the new area by the original area: 2.25s^2 / s^2 = 2.25. Therefore, the ratio between the new area and the original area of the square can be represented as 2.25 : 1 which means for every 1 unit of original area, the new area is 2.25 unit.
- A. Rs. 87.50
- B. Rs. 84.70
- C. Rs. 87.20
- D. Rs. 77.50
Remarks:
Explanation:
Ratio between the sides of rectangle = 3: 4 Let the ratio constant be x then, Length = 3x and breadth = 4x Area = L x B 7500=3x × 4x=12x^2 7500/12= x^2=625 x=25 Length = 3 x 25 = 75 m, and Breadth = 4 x 25 = 100 m Perimeter = 2(75 + 100) = 2 x 175 = 350 m Cost of fencing 1 meter = 25 paise Cost of fencing 350 m = 350 x 25 = 8750 paise In rupees: Rs. 87.50
- A. 21.92 m<sup>2</sup>
- B. 17.92 m<sup>2</sup>
- C. 22.92 m<sup>2</sup>
- D. 25.92 m<sup>2</sup>
Remarks:
Explanation:
Area of the square = 1/2 (diagonal)^2= 1/2x7.2^2≡ 7.2x7.2/2=25.92 m2
- A. 34 cm
- B. 48 cm
- C. 63 cm
- D. 23 cm
Remarks:
Explanation:
Side of first square = (80/4) = 20 cm; Side of second square = (64/4)cm = 16 cm. Area of third square = [(20)^2 - (16)^2] cm^2 = (400 - 256) cm^2 = 144 cm^2. Side of third square = √144 cm = 12 cm. Required perimeter = (12 x 4) cm = 48 cm.
- A. 34.56 %
- B. 32.43 %
- C. 29.45 %
- D. 45.24 %
Remarks:
Explanation:
Let each side of the square be X. Then, area = X^2. New side =(116X/100) =(29X/25). New area = (29X/25)^2 Increase in area = (29X/25)^2 - X^2 =841/625X^2 - X^2=216/625X^2 ⇒ Increase% = [(216/625X^2x1/(X^2))*100] % = 34.56%.