Q: The perimeters of two squares are 80 cm and 64 cm, respectively. Determine the perimeter of a third square whose area equals the difference between the two squares' areas.
Side of first square = (80/4) = 20 cm;
Side of second square = (64/4)cm = 16 cm.
Area of third square = [(20)^2 - (16)^2] cm^2
= (400 - 256) cm^2 = 144 cm^2.
Side of third square = √144 cm = 12 cm.
Required perimeter = (12 x 4) cm = 48 cm.