C program to find that entered year is leap year or not

C Programming Language Decision Making of C Language (Article) Decision Making of C Language (Program)

1381

Program:

/* Program to find that entered year is leap year or not.
   Author: Atnyla Developer */

// C program to check if a given year is leap year or not
#include <stdio.h>
#include <stdbool.h>
 
bool checkYear(int year)
{
    // If a year is multiple of 400, then it is a leap year
    if (year%400 == 0)
        return true;
 
    // Else If a year is muliplt of 100, then it is not a
    // leap year
    if (year%100 == 0)
        return false;
 
    // Else If a year is muliplt of 4, then it is a leap year
    if (year%4 == 0)
        return true;
    return false;
}
 
 
int main()
{
    int year;
    printf("Enter a year to be check \n");
    scanf("%d", &year);
 
    checkYear(year)? printf("Leap Year \n"): printf("Not a Leap Year \n");
 
    return 0;
} 

Output:

enter any year: 2012
year is a leap year
Press any key to continue . . .

Enter a year to be check
2100
Not a Leap Year
Press any key to continue . . .

Explanation:

A year is leap year if following conditions are satisfied
1) Year is multiple of 400
2) Year is multiple of 4 and not multiple of 100.

Following is pseudo code

if year is divisible by 400 then is_leap_year
else if year is divisible by 100 then not_leap_year
else if year is divisible by 4 then is_leap_year
else not_leap_year

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