Slice list into 3 equal chunks and reverse each chunk

Python Python List (Article) Python List (Program)

1163

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• Divide the length of a list by 3 to get the each chunk size
• Run loop three times and use the slice() function to get the chunk and reverse it

Given Input:

sample_list = [11, 45, 8, 23, 14, 12, 78, 45, 89]

Expected Output:

Chunk  1 [11, 45, 8]
After reversing it  [8, 45, 11]
Chunk  2 [23, 14, 12]
After reversing it  [12, 14, 23]
Chunk  3 [78, 45, 89]
After reversing it  [89, 45, 78]

Program:

sample_list = [11, 45, 8, 23, 14, 12, 78, 45, 89]
print("Original list ", sample_list)

length = len(sample_list)
chunk_size = int(length / 3)
start = 0
end = chunk_size

# run loop 3 times
for i in range(3):
    # get indexes
    indexes = slice(start, end)
    
    # get chunk
    list_chunk = sample_list[indexes]
    print("Chunk ", i, list_chunk)
    
    # reverse chunk
    print("After reversing it ", list(reversed(list_chunk)))

    start = end
    end += chunk_size

Output:

Original list  [11, 45, 8, 23, 14, 12, 78, 45, 89]
Chunk  0 [11, 45, 8]
After reversing it  [8, 45, 11]
Chunk  1 [23, 14, 12]
After reversing it  [12, 14, 23]
Chunk  2 [78, 45, 89]
After reversing it  [89, 45, 78]

Explanation:

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