Ratio and Proportion - Quiz

Here's another way to calculate C's share:

C's share = C's ratio * (total amount / sum of ratios)
= 5 * (1260 / 10)
= 5 * 126
= 630

Let X be the value of 1 unit in terms of the currency being used.
Then, the initial expenditure on salary is 12 units * X = 12X.

We are given that 2 units = 12000, so we can set up the following equation:
2X = 12000.
Solving this equation gives us X = 6000.

Substituting this value back into the equation for the initial expenditure on salary, we find that the initial expenditure on salary is 12 units * 6000 = 72000.

Therefore, the initial expenditure on salary is 72000.

Distance covered in the ratio T: B: C = 4: 3: 2
Fair ratio per km. T: B: C = 1: 2: 4
So, the ratio of total fair T: B: C = 4: 6: 8

Sum of the ratio of total fair = 18
But ATQ, it is 720, so multiply 18 by 40.
Now, multiply each and every ratio with 40.
The total expenditure as fair on a train = 4*40=160

If the ratio of coins = 4: 6: 9
That means if Rs 5 coins are 4, Rs 2 coins are 6, and then Rs 1 coins are 9.

According to the given ratio, the ratio of amounts = 5*4: 6*2: 9*1 = 20: 12: 9
The sum of the ratios of the amounts = 20+12+9 = Rs 41
But ATQ, it is Rs 410, which means multiply each ratio by 10
i.e., new ratio = 40: 60: 90
Now, 40*5: 60*2: 90*1 = 200: 120: 90

The total amount in the form of two rupees coins = 120
So, the two rupees coins = 120/2= 60

The ratio of land: water = 1: 2
In the northern hemisphere the ration of land: water = 2: 3

Note: Earth is divided equally into two hemispheres called northern hemisphere and southern hemisphere.

i.e., the northern hemisphere is 50% of the total earth.

We can say southern hemisphere = total area- northern hemisphere.

To make the northern hemisphere 50% of the total area
Multiply the ratio of the earth by 10 and northern hemisphere by 3
Now, earth's ratio Land: water = 1*10: 2*10 = 10: 20............... (i)
Northern hemisphere's ratio = 2*3: 3*3 = 6: 9...................... (ii)

Subtract equation i by ii

Hence, southern hemisphere = 10- 6: 20-9 = 4: 11

 Let 40% of A = 2/3 B. Then,
40A/100 = 2B/3 => 2A/5 = 2B/3
A/B = (2/3 * 5/2) = 5/3
Hence, A : B = 5 : 3

1/3 : 1/2 : 1/1 = 2 : 3 : 6

Let the soldiers in the two armies be 10X, 3X and losses be 20Y, 3Y,

Then we have,

survivors in the larger army

10X - 20Y = 24000 ...(i)

Likewise survivors in the smaller army

And 3X - 3Y = 24000 x 13/40 = 7800 -----(ii)

Solving, we have 10X = 28000, 3X = 8400

The first alloy is prepared by mixing metals in proportions 7 : 2,
Then the weight of the first alloy will be = 7x + 2x
Assume ’x’ = 1Kg
The weight of the first alloy will be 9kg
The second alloy is prepared by mixing metals in proportions 7 : 11,
The weight of the second alloy will be 18kg
If equal quantities of the two alloys are melted to form a third alloy,
Then 18Kg of first alloy should be used, then its ratio will become 14 : 4,
Now, the proportion of argentum and brass in third alloy = 7 + 14 : 11 + 4 = 21 : 15 = 7 : 5

Let X’s income be 3k then Y’s income is 4k.
Let X’s expenditure be 4g then Y’s expenditure is 5g.
But 3k = 9/10 (5g) or k = 3/2g
X’s saving/Y’s saving = (3k - 4g)/(4k - 5g)
[3 (3 / 2g) - 4g]/[ 4(3 / 2g) - 5g] = 1/2
X’s saving : Y’s saving = 1 : 2