Ratio and Proportion - Quiz

Here's another way to calculate C's share:

C's share = C's ratio * (total amount / sum of ratios)
= 5 * (1260 / 10)
= 5 * 126
= 630

To find the ratio of A: B: C: D, you can follow these steps:

Find the ratio of A to B: A: B = 1: 2
Find the ratio of B to C: B: C = 3: 2
Find the ratio of C to D: C: D = 1: 3
Multiply all the ratios together: A: B: C: D = (131): (231): (221): (223) = 3: 6: 4: 12
This gives you the ratio of A to B to C to D as 3: 6: 4: 12.

Let X be the total income of Pervez, Sunny, and Ashu.
Then, Pervez's salary is X * 16/37.
Sunny's salary is X * 12/37.
Ashu's salary is X * 9/37.

We are given that Pervez's saving is 20% of his income, Sunny's saving is 25% of his income, and Ashu's saving is 40% of his income, so we can set up the following equations:
X * 16/37 * 20/100 = X * 16/37 * 1/5 = X * 16/185 = X * 16/185 * 100/100 = X * 16/185 * 1
X * 12/37 * 25/100 = X * 12/37 * 1/4 = X * 12/148 = X * 12/148 * 100/100 = X * 12/148 * 1
X * 9/37 * 40/100 = X * 9/37 * 2/5 = X * 9/74 = X * 9/74 * 100/100 = X * 9/74 * 1

Adding these equations gives us:
X = 1530.

Substituting this value back into the equation for Sunny's salary, we find that Sunny's salary is 1530 * 12/37 = 480.

Therefore, Sunny's salary is 480.

Distance covered in the ratio T: B: C = 4: 3: 2
Fair ratio per km. T: B: C = 1: 2: 4
So, the ratio of total fair T: B: C = 4: 6: 8

Sum of the ratio of total fair = 18
But ATQ, it is 720, so multiply 18 by 40.
Now, multiply each and every ratio with 40.
The total expenditure as fair on a train = 4*40=160

Given ratio = 3: 2: 1
Or, 3x: 2x: x
The initial price= (6x)2 = 36x2
After broke down the price = (3x)2: (2x)2: x2 = 9x2: 4x2: x2 = 14x2
After breakdown, a loss of Rs. 4620 occurs.
i.e., loss = initial price - final price
Loss = 36x2 - 14x2 = 22x2
22x2 = 4620
Or, x2 =4620/22 = 210
The initial price of silver-biscuit = 36*210 = 7560

 Let the ages of Kunal and sagar be x and y respectively.
According to the equation, (x-6)/(y-6) = 6/5
=> (x+4)/(y+4) = 11/10
After solving we get y = 16

The savings of Chetan and Dinesh are 3x – 5y and 4x – 7y respectively.
3x – 5y = 200 --- (1)
4x – 7y = 200 --- (2)
Multiplying (1) by 7 and (2) by 5 and subtracting the resultant equation (2) from resultant equation (1), we get x = 400.
The incomes of Chetan and Dinesh are 3x = Rs.1200 and 4x = Rs.1600 respectively.

 Let the third number be x
Then, first number = 120% of x = 120x/100 = 6x/5
Second number = 150% of x = 150x/100 = 3x/2
Ratio of first two numbers = 6x/5 : 3x/2 = 12x : 15x = 4 : 5

Let X’s income be 3k then Y’s income is 4k.
Let X’s expenditure be 4g then Y’s expenditure is 5g.
But 3k = 9/10 (5g) or k = 3/2g
X’s saving/Y’s saving = (3k - 4g)/(4k - 5g)
[3 (3 / 2g) - 4g]/[ 4(3 / 2g) - 5g] = 1/2
X’s saving : Y’s saving = 1 : 2

Let x and y be the two numbers
Therefore, (x/y) = (2/3),
(x + 8)/(y + 8) = 3/4 => x = 16, y = 24