- A10 km/hr.
- B20 km/hr.
- C30 km/hr.
- D40 km/hr.
General Aptitude - Quiz
- A15%
- B38/3%
- C300/11%
- D69/4%
- A20 kmph
- B24 kmph
- C28 kmph
- D32 kmph
- A4 : 5
- B4 : 3
- C3 : 5
- D2 : 5
Results:
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🟢 Correct Answers: 🔴 Wrong Answers:
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General Aptitude - Quiz
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Time Taken: Questions: Answered: Not Answered:
Correct Answer:
Wrong Answer:
Percentage: %
- A. 10 km/hr.
- B. 20 km/hr.
- C. 30 km/hr.
- D. 40 km/hr.
Remarks:
Explanation: Option D
- A. 125m
- B. 135m
- C. 150m
- D. 175m
Remarks:
Explanation: The answer is the Option C
- A. 25
- B. 30
- C. 40
- D. 45
Remarks:
Explanation: The Option B is the correct answer
- A. 15%
- B. 38/3%
- C. 300/11%
- D. 69/4%
Remarks:
Explanation:
To find the gain percentage, you can use the following formula: Gain percentage = (Gain / Cost) * 100 In this case, the cost is 100 - 15 = Rs.85 and the gain is 15, so the gain percentage is: Gain percentage = (15 / 85) * 100 This simplifies to: Gain percentage = 15/17* 20 So the gain percentage is 300/17%.
- A. 11:7
- B. 7:4
- C. 7:3
- D. 9:5
Remarks:
Explanation:
If the age of the mother 10 years ago was 3 times the age of her son, and the mother's age in 10 years will be twice the age of her son, the equation can be represented as: 3x+10+10=2(x+10+10) 3x+20=2x+40 x=20 The present ratio of the mother's age to the son's age is (3x+10):(x+10) = (3*20+10):(20+10) = 70:30 = 7:3.
- A. 26
- B. 10
- C. 9
- D. 4
Remarks:
Explanation:
According to the calculation,
the ratio of the number of men to the number of women required to reap the field is 1:3/2.
This means that for every 1 man,
3/2 women are required.
The calculation also shows that the total number of men and women required to reap the field is equivalent to 28 women.
Using this information,
we can determine that it will take 28 women,
or the equivalent number of men and women,
9 days to reap the field.
This is because 18 women can reap the field in 14 days,
and 28 women is a greater number,
so it will take longer to complete the work
- A. 20 kmph
- B. 24 kmph
- C. 28 kmph
- D. 32 kmph
Remarks:
Explanation:
<span class="pln"> </span><span class="typ">The</span><span class="pln"> distance </span><span class="kwd">from</span><span class="pln"> A to B </span><span class="kwd">is</span><span class="pln"> given </span><span class="kwd">as</span><span class="pln"> d km</span><span class="pun">.</span><span class="pln"> </span><span class="typ">The</span><span class="pln"> average speed </span><span class="kwd">is</span><span class="pln"> calculated </span><span class="kwd">using</span><span class="pln"> the formula average speed </span><span class="pun">=</span><span class="pln"> total distance traveled </span><span class="pun">/</span><span class="pln"> total time taken</span><span class="pun">.</span><span class="pln"> </span><span class="typ">The</span><span class="pln"> total distance traveled </span><span class="kwd">is</span><span class="pln"> given </span><span class="kwd">as</span><span class="pln"> </span><span class="lit">2d</span><span class="pln"> km</span><span class="pun">,</span><span class="pln"> which </span><span class="kwd">is</span><span class="pln"> the distance </span><span class="kwd">from</span><span class="pln"> A to B plus the distance </span><span class="kwd">from</span><span class="pln"> B to A</span><span class="pun">.</span><span class="pln"> </span><span class="typ">The</span><span class="pln"> total time taken </span><span class="kwd">is</span><span class="pln"> calculated </span><span class="kwd">by</span><span class="pln"> adding the time taken to travel </span><span class="kwd">from</span><span class="pln"> A to B to the time taken to travel </span><span class="kwd">from</span><span class="pln"> B to A</span><span class="pun">.</span><span class="pln"> </span><span class="typ">The</span><span class="pln"> time taken to travel </span><span class="kwd">from</span><span class="pln"> A to B </span><span class="kwd">is</span><span class="pln"> given </span><span class="kwd">as</span><span class="pln"> d</span><span class="pun">/</span><span class="lit">20</span><span class="pln"> hours</span><span class="pun">,</span><span class="pln"> </span><span class="kwd">and</span><span class="pln"> the time taken to travel </span><span class="kwd">from</span><span class="pln"> B to A </span><span class="kwd">is</span><span class="pln"> given </span><span class="kwd">as</span><span class="pln"> d</span><span class="pun">/</span><span class="lit">30</span><span class="pln"> hours</span><span class="pun">.</span><span class="pln"> </span><span class="typ">Plugging</span><span class="pln"> the values </span><span class="kwd">for</span><span class="pln"> total distance traveled </span><span class="kwd">and</span><span class="pln"> total time taken </span><span class="kwd">into</span><span class="pln"> the formula </span><span class="kwd">for</span><span class="pln"> average speed</span><span class="pun">,</span><span class="pln"> we </span><span class="kwd">get</span><span class="pln"> average speed </span><span class="pun">=</span><span class="pln"> </span><span class="pun">(</span><span class="lit">2d</span><span class="pln"> km</span><span class="pun">)</span><span class="pln"> </span><span class="pun">/</span><span class="pln"> </span><span class="pun">[(</span><span class="pln">d</span><span class="pun">/</span><span class="lit">20</span><span class="pln"> hours</span><span class="pun">)</span><span class="pln"> </span><span class="pun">+</span><span class="pln"> </span><span class="pun">(</span><span class="pln">d</span><span class="pun">/</span><span class="lit">30</span><span class="pln"> hours</span><span class="pun">)].</span><span class="pln"> </span><span class="typ">Simplifying</span><span class="pln"> the expression </span><span class="kwd">for</span><span class="pln"> total time taken</span><span class="pun">,</span><span class="pln"> we </span><span class="kwd">get</span><span class="pln"> average speed </span><span class="pun">=</span><span class="pln"> </span><span class="pun">(</span><span class="lit">2d</span><span class="pln"> km</span><span class="pun">)</span><span class="pln"> </span><span class="pun">/</span><span class="pln"> </span><span class="pun">[</span><span class="lit">5d</span><span class="pun">/</span><span class="lit">60</span><span class="pln"> hours</span><span class="pun">].</span><span class="pln"> </span><span class="typ">Finally</span><span class="pun">,</span><span class="pln"> we can solve </span><span class="kwd">for</span><span class="pln"> the average speed </span><span class="kwd">by</span><span class="pln"> dividing both sides </span><span class="kwd">of</span><span class="pln"> the equation </span><span class="kwd">by</span><span class="pln"> </span><span class="lit">5d</span><span class="pun">/</span><span class="lit">60</span><span class="pln"> hours</span><span class="pun">,</span><span class="pln"> which gives us average speed </span><span class="pun">=</span><span class="pln"> </span><span class="pun">(</span><span class="lit">2d</span><span class="pln"> km</span><span class="pun">)</span><span class="pln"> </span><span class="pun">/</span><span class="pln"> </span><span class="pun">(</span><span class="lit">5d</span><span class="pun">/</span><span class="lit">60</span><span class="pln"> hours</span><span class="pun">)</span><span class="pln"> </span><span class="pun">=</span><span class="pln"> </span><span class="lit">24</span><span class="pln"> km</span><span class="pun">/</span><span class="pln">hr </span>
- A. 4 : 5
- B. 4 : 3
- C. 3 : 5
- D. 2 : 5
Remarks:
Explanation:
<span class="pln"> </span><span class="typ">Let</span><span class="pln"> the third number be x </span><span class="typ">Then</span><span class="pun">,</span><span class="pln"> first number </span><span class="pun">=</span><span class="pln"> </span><span class="lit">120</span><span class="pun">%</span><span class="pln"> </span><span class="kwd">of</span><span class="pln"> x </span><span class="pun">=</span><span class="pln"> </span><span class="lit">120x</span><span class="pun">/</span><span class="lit">100</span><span class="pln"> </span><span class="pun">=</span><span class="pln"> </span><span class="lit">6x</span><span class="pun">/</span><span class="lit">5</span><span class="pln"> </span><span class="typ">Second</span><span class="pln"> number </span><span class="pun">=</span><span class="pln"> </span><span class="lit">150</span><span class="pun">%</span><span class="pln"> </span><span class="kwd">of</span><span class="pln"> x </span><span class="pun">=</span><span class="pln"> </span><span class="lit">150x</span><span class="pun">/</span><span class="lit">100</span><span class="pln"> </span><span class="pun">=</span><span class="pln"> </span><span class="lit">3x</span><span class="pun">/</span><span class="lit">2</span><span class="pln"> </span><span class="typ">Ratio</span><span class="pln"> </span><span class="kwd">of</span><span class="pln"> first two numbers </span><span class="pun">=</span><span class="pln"> </span><span class="lit">6x</span><span class="pun">/</span><span class="lit">5</span><span class="pln"> </span><span class="pun">:</span><span class="pln"> </span><span class="lit">3x</span><span class="pun">/</span><span class="lit">2</span><span class="pln"> </span><span class="pun">=</span><span class="pln"> </span><span class="lit">12x</span><span class="pln"> </span><span class="pun">:</span><span class="pln"> </span><span class="lit">15x</span><span class="pln"> </span><span class="pun">=</span><span class="pln"> </span><span class="lit">4</span><span class="pln"> </span><span class="pun">:</span><span class="pln"> </span><span class="lit">5</span>
- A. 15000
- B. 16000
- C. 20000
- D. 10000
Remarks:
Explanation:
Option B
- A. 45.5
- B. 48.9
- C. 49.9
- D. 46.8
Remarks:
Explanation:
Output:
- total weight of 50 students=(45×50)kg=2250kg
Average weight of 49 students=[45kg-100g]
=44.9kg
Total weight of 49 students=(44.9×49)kg=2200.1kg.
Weight of the student who left the class=(2250-2200.1)kg=49.9kg.