Program to print the given number pattern
1
23
345
4567
56789

C Programming Language Loop control in C Language (Article) Loop control in C Language (Program)

6233

Program:

/**
 * C program to print number pattern
 */

#include <stdio.h>

int main()
{
    int i, j, k, N;

    printf("Enter N: ");
    scanf("%d", &N);

    for(i=1; i<=N; i++)
    {
        k = i;

        // Logic to print numbers
        for(j=1; j<=i; j++, k++)
        {
            printf("%d", k);
        }

        printf("\n");
    }

    return 0;
}

Output:

Enter N: 5
1
23
345
4567
56789

Explanation:

Logic to print the given number pattern

 

1
23
345
4567
56789

 

Before I discuss logic to print the given number pattern, I recommend you that have a close look to the pattern carefully for a couple of minutes. The above pattern consists of N rows (where N is the total number of rows to be printed). Each row contains i columns (where i is the current row number). To print the above pattern we will be using an extra variable say k that will keep the value which we need to print.
Step-by-step descriptive logic:

  1. To iterate through rows, run an outer loop from 1 to N.
  2. Inside the outer loop initialize k = i (where k is an extra variable which will hold the number which we need to print next and i is the current row number).
  3. To print the numbers, run an inner loop from 1 to i. Inside this loop print the value of k. Also increment the value of k after printing.

And you are done, lets implement this.


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