Java program to check armstrong number

Java Programming Language Decision Making and Looping in java (Article) Decision Making and Looping in java (Program)

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Write a program to find out the Armstrong number using user input.: This java program checks if a number is Armstrong or not. Armstrong number is a number which is equal to sum of digits raise.

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Program:

import java.util.Scanner;
 
class ArmstrongNumber
{
   public static void main(String args[])
   {
      int n, sum = 0, temp, remainder, digits = 0;
 
      Scanner in = new Scanner(System.in);
      System.out.println("Input a number to check if it is an Armstrong number");      
      n = in.nextInt();
 
      temp = n;
 
      // Count number of digits
 
      while (temp != 0) {
         digits++;
         temp = temp/10;
      }
 
      temp = n;
 
      while (temp != 0) {
         remainder = temp%10;
         sum = sum + power(remainder, digits);
         temp = temp/10;
      }
 
      if (n == sum)
         System.out.println(n + " is an Armstrong number.");
      else
         System.out.println(n + " is not an Armstrong number.");         
   }
 
   static int power(int n, int r) {
      int c, p = 1;
 
      for (c = 1; c <= r; c++) 
         p = p*n;
 
      return p;   
   }
}

Output:

Output 1:
Input a number to check if it is an Armstrong number
45781
45781 is not an Armstrong number.
Output 2:
 Input a number to check if it is an Armstrong number
9926315
9926315 is an Armstrong number.
 

Explanation:

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