Write a program to input twenty names in an array. Arrange these names in descending order of letters, using the bubble sort technique.
Java Programming Language (Article) (Program)
30
Given Input:
Expected Output:
Program:
import java.util.Scanner;
public class RAnsariArrangeNames
{
public static void main(String args[]) {
Scanner in = new Scanner(System.in);
String names[] = new String[20];
System.out.println("Enter 20 names:");
for (int i = 0; i < names.length; i++) {
names[i] = in.nextLine();
}
//Bubble Sort
for (int i = 0; i < names.length - 1; i++) {
for (int j = 0; j < names.length - 1 - i; j++) {
if (names[j].compareToIgnoreCase(names[j + 1]) < 0) {
String temp = names[j + 1];
names[j + 1] = names[j];
names[j] = temp;
}
}
}
System.out.println("\nSorted Names");
for (int i = 0; i < names.length; i++) {
System.out.println(names[i]);
}
}
}
Output:
This Particular section is dedicated to Programs only. If you want learn more about Java Programming Language. Then you can visit below links to get more depth on this subject.
Program:
import java.util.Scanner; public class RAnsariArrangeNames { public static void main(String args[]) { Scanner in = new Scanner(System.in); String names[] = new String[20]; System.out.println("Enter 20 names:"); for (int i = 0; i < names.length; i++) { names[i] = in.nextLine(); } //Bubble Sort for (int i = 0; i < names.length - 1; i++) { for (int j = 0; j < names.length - 1 - i; j++) { if (names[j].compareToIgnoreCase(names[j + 1]) < 0) { String temp = names[j + 1]; names[j + 1] = names[j]; names[j] = temp; } } } System.out.println("\nSorted Names"); for (int i = 0; i < names.length; i++) { System.out.println(names[i]); } } }
Output:
This Particular section is dedicated to Programs only. If you want learn more about Java Programming Language. Then you can visit below links to get more depth on this subject.