check if a number is a palindrome in Java
Mathematics for Programming Numbers (Article) Numbers (Program)
52
-
Understanding Palindrome Numbers: A palindrome number reads the same backward as forward. For example, 121 and 1331 are palindromes.
-
Steps to Check for Palindrome Numbers:
- Convert the number to a string.
- Reverse the string.
- Compare the original string with the reversed string.
Given Input:
12321
Expected Output:
12321 is a palindrome.
Program:
public class PalindromeChecker {
public static boolean isPalindrome(int number) {
// Convert number to string
String original = String.valueOf(number);
// Reverse the string
String reversed = new StringBuilder(original).reverse().toString();
// Check if original and reversed strings are equal
return original.equals(reversed);
}
public static void main(String[] args) {
int number = 12321; // Example number to check
if (isPalindrome(number)) {
System.out.println(number + " is a palindrome.");
} else {
System.out.println(number + " is not a palindrome.");
}
}
}
Output:
12321 is a palindrome.
Explanation:
-
isPalindrome(int number)
method checks if number
is a palindrome.
- It first converts
number
to a string using String.valueOf(number)
.
- It uses
StringBuilder
to reverse the string representation of number
.
- It compares the original string (
original
) with the reversed string (reversed
) using the equals
method.
- If they are equal, the number is a palindrome; otherwise, it's not.
Check if a Number is a Palindrome:
Steps to Check if a Number is a Palindrome:
- Reverse the Digits: Reverse the digits of the number.
- Compare: Compare the original number with the reversed number.
import java.util.Scanner;
public class PalindromeExample {
public static void main(String[] args) {
int n, r, sum = 0, temp;
Scanner scanner = new Scanner(System.in);
System.out.print("Enter the Number: ");
n = scanner.nextInt(); // Read the input number
temp = n; // Store the original number
// Reverse the number
while (n > 0) {
r = n % 10; // Get the last digit
sum = (sum * 10) + r; // Build the reversed number
n = n / 10; // Remove the last digit
}
// Check if the original number and the reversed number are the same
if (temp == sum) {
System.out.println("Number is Palindrome.");
} else {
System.out.println("Number is not Palindrome.");
}
scanner.close(); // Close the scanner
}
}
- Scanner: Used to take input from the user.
- Variables:
-
n
: The input number.
-
r
: The remainder when dividing by 10 (the last digit).
-
sum
: The reversed number.
-
temp
: A temporary variable to store the original number for comparison.
- Reversing the Number:
- In the
while
loop, extract the last digit of n
using n % 10
and append it to sum
.
- Update
n
by removing the last digit (n = n / 10
).
- Comparison:
- After the loop, compare the original number (
temp
) with the reversed number (sum
).
- Print the result based on the comparison.
This Particular section is dedicated to Programs only. If you want learn more about Mathematics for Programming. Then you can visit below links to get more depth on this subject.
12321 is a palindrome.
Program:
public class PalindromeChecker { public static boolean isPalindrome(int number) { // Convert number to string String original = String.valueOf(number); // Reverse the string String reversed = new StringBuilder(original).reverse().toString(); // Check if original and reversed strings are equal return original.equals(reversed); } public static void main(String[] args) { int number = 12321; // Example number to check if (isPalindrome(number)) { System.out.println(number + " is a palindrome."); } else { System.out.println(number + " is not a palindrome."); } } }
Output:
12321 is a palindrome.
Explanation:
-
isPalindrome(int number)
method checks ifnumber
is a palindrome. - It first converts
number
to a string usingString.valueOf(number)
. - It uses
StringBuilder
to reverse the string representation ofnumber
. - It compares the original string (
original
) with the reversed string (reversed
) using theequals
method. - If they are equal, the number is a palindrome; otherwise, it's not.
Check if a Number is a Palindrome:
Steps to Check if a Number is a Palindrome:
- Reverse the Digits: Reverse the digits of the number.
- Compare: Compare the original number with the reversed number.
import java.util.Scanner; public class PalindromeExample { public static void main(String[] args) { int n, r, sum = 0, temp; Scanner scanner = new Scanner(System.in); System.out.print("Enter the Number: "); n = scanner.nextInt(); // Read the input number temp = n; // Store the original number // Reverse the number while (n > 0) { r = n % 10; // Get the last digit sum = (sum * 10) + r; // Build the reversed number n = n / 10; // Remove the last digit } // Check if the original number and the reversed number are the same if (temp == sum) { System.out.println("Number is Palindrome."); } else { System.out.println("Number is not Palindrome."); } scanner.close(); // Close the scanner } }
- Scanner: Used to take input from the user.
- Variables:
-
n
: The input number. -
r
: The remainder when dividing by 10 (the last digit). -
sum
: The reversed number. -
temp
: A temporary variable to store the original number for comparison.
-
- Reversing the Number:
- In the
while
loop, extract the last digit ofn
usingn % 10
and append it tosum
. - Update
n
by removing the last digit (n = n / 10
).
- In the
- Comparison:
- After the loop, compare the original number (
temp
) with the reversed number (sum
). - Print the result based on the comparison.
- After the loop, compare the original number (
This Particular section is dedicated to Programs only. If you want learn more about Mathematics for Programming. Then you can visit below links to get more depth on this subject.