Higher order functions and closures - 2 - Hands On

Python Python Function (Article) Python Function (Program)

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2. Higher order functions and closures - 2

• Define a function factory, with a variable n initialized to zero, and two inner functions current and counter.

• current must return the current value of n.

• counter must increment the value of n by one.

Hint: Check the closure functions f_current and f_counter, and return the current and counter functions from factory accordingly.

• Use the 'Test against custom input' box to output the result for debugging. Provide an integer (refer test case samples) to display the output / error.

Given Input:

2

Expected Output:

2
3

Code Hints:

#!/bin/python3

import sys
import os



# Add the factory function implementation here


f_current, f_counter = factory(int(input()))

if __name__ == "__main__":
    with open(os.environ['OUTPUT_PATH'], 'w') as fout:
        func_lst = [f_current, f_counter]
        res_lst = list()
        for func in func_lst:
            res_lst.append(func())
        fout.write("{}\n{}".format(*res_lst))

Program:

#!/bin/python3


import sys

import os


# Add the factory function implementation here

def factory(v):

    n=0

    def current():

        n=v

        print(n)

        return n

    def counter():

        n = v + 1

        print(n)

        return n

    return current, counter


f_current, f_counter = factory(int(input()))

if __name__ == "__main__":
    with open(os.environ['OUTPUT_PATH'], 'w') as fout:
        func_lst = [f_current, f_counter]
        res_lst = list()
        for func in func_lst:
            res_lst.append(func())
        fout.write("{}\n{}".format(*res_lst))

Output:

 Test Case Input: 
89


 Test Case Expected Output: 
89
90

 

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