Q: A man walks 6 kilometres at 1 1/2 kmph, runs 8 km at 2 kmph, and takes the bus another 32 km. The bus travels at an average speed of 8 kilometres per hour. Determine the man's average speed.  

The person traveled a distance of 6 km at a speed of 1.5 km/hr. The time taken for this leg of the journey is given as 6 km / 1.5 km/hr = 4 hours.

The person traveled a distance of 8 km at a speed of 2 km/hr. The time taken for this leg of the journey is given as 8 km / 2 km/hr = 4 hours.

The person traveled a distance of 32 km at a speed of 8 km/hr. The time taken for this leg of the journey is given as 32 km / 8 km/hr = 4 hours.

The total distance traveled by the person is given as the sum of the distances traveled in each leg of the journey, which is 6 km + 8 km + 32 km = 46 km.

The total time taken by the person is given as the sum of the times taken for each leg of the journey, which is 4 hours + 4 hours + 4 hours = 12 hours.

To find the average speed of the person, we can use the formula average speed = total distance / total time. Plugging in the values given in the problem, we get average speed = 46 km / 12 hours = 3 (5/6) km/hr.