The electric field intensity E at a distance r from a point charge q is given by E = k*q/r^2, where k is the electrostatic constant. The electric potential V at that distance is given by V = k*q/r. Given that E = 32 N/C and V = 16 J/C, we can equate the two expressions and solve for r. Therefore, 32 N/C = (16 J/C) / r. Rearranging the equation, we have r = (16 J/C) / 32 N/C = 0.5 m.