What will be the result stored in x after evaluating the following expression? 

int x = 4;
x += (x++) + (++x) + x;

Views 13

Answer:


    x += (x++) + (++x) + x
⇒ x = x + ((x++) + (++x) + x)
⇒ x = 4 + (4 + 6 + 6)
⇒ x = 4 + 16
⇒ x = 20


class Student {

    // Main method to create an object of the class and call the member methods
    public static void main(String[] args) {
        int x = 4;
        x += (x++) + (++x) + x;
        System.out.println("The value of x is: " + x); // Corrected to print the value of x
    }
}

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